A force of 30 N is applied to the larger arm of the lever. What force is applied to the smaller
| June 30, 2021 | education
A force of 30 N is applied to the larger arm of the lever. What force is applied to the smaller arm if the arms of the lever in equilibrium are equal to 30 cm and 15 cm.
These tasks: F1 (force applied to the larger arm of the lever) = 30 N; the lever in question is in equilibrium; l1 (longer shoulder length) = 30 cm; l2 (length of the smaller shoulder) = 15 cm.
The force applied to the smaller arm is determined from the equality: F1 * l1 = M (moment of force) = F2 * l2, whence F2 = F1 * l1 / l2.
Calculation: F2 = 30 * 30/15 = 60 N.
Answer: A force of 60 N is applied to the smaller shoulder.
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