A force of 300 N acts on the small arm of the lever, and 20 N on the large arm.

| February 23, 2021 | education

A force of 300 N acts on the small arm of the lever, and 20 N on the large arm. The length of the small arm is 5 cm. Find the length of the large arm.

Given:

N1 = 300 Newton – the magnitude of the force acting on the small lever arm;

N2 = 20 Newton – the magnitude of the force acting on the large arm of the lever;

a = 5 centimeters – the length of the small lever arm.

It is required to determine b (meter) – the length of the large lever arm.

We will convert the units of measurement of length to the SI system:

a = 5 cm = 5 * 10 ^ -2 = 5/100 = 0.05 meters.

Since the condition of the problem is not specified, we consider the lever itself to be weightless and balanced. Then, by the rule of the lever:

N2 * b = N1 * a;

b = N2 * a / N1 = 300 * 0.05 / 20 = 15/20 = 0.75 meters.

Answer: The length of the large lever arm is 0.75 meters.



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