A freight train departed from the station, going at a speed of 36 km / h, after 0.5 in the same direction

| September 8, 2021 | education

A freight train departed from the station, going at a speed of 36 km / h, after 0.5 in the same direction, a fast train departed, at a speed of 72 m / h. How long after the goods train left the fast train will catch up with it?

To find the time during which a fast train caught up with a freight train, we use the equality: Vt * (t + Δt) = S (distance traveled by the trains) = Vc * t, whence Vt * t + Vt * Δt – Vc * t = 0 and t = Vt * Δt / (Vc – Vt).

Variables: Vt is the speed of a freight train (Vt = 36 km / h); Δt is the difference in movement time (Δt = 0.5 h); Vс – speed of a fast train (Vс = 72 km / h).

Calculation: t = VT * Δt / (Vs – VT) = 36 * 0.5 / (72 – 36) = 0.5 h.

Answer: The fast train should catch up with the freight train in 0.5 hours.



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