A freight train moving away from a place moved with an acceleration of 0.5 m / s and accelerated
| September 26, 2021 | education
A freight train moving away from a place moved with an acceleration of 0.5 m / s and accelerated to a speed of 36 km / h which way it traveled at the same time.
Initial data: a (acceleration with which the freight train was moving) = 0.5 m / s ^ 2; V (the speed to which the freight train accelerated) = 36 km / h = 10 m / s; V0 (initial speed of the freight train) = 0 m / s.
The distance traveled by the freight train is determined by the formula: S = (V ^ 2 – V0 ^ 2) / 2a = V ^ 2 / 2a.
Let’s perform the calculation: S = 10 ^ 2 / (2 * 0.5) = 100 m.
Answer: The freight train has traveled 100 meters.
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