A freight tram car for 10 hours of operation consumes 23.76 * 10 ^ 5 kJ of electricity. Determine the power of the tram engine.
| February 16, 2021 | education
The power of a tram engine can be found by dividing the consumed energy W (in joules) by the time t (in seconds):
W = 23.76 * 10 ^ 5 kJ = 23.76 * 10 ^ 8 J;
t = 10 hours = 36,000 s;
P = W / t = (23.76 * 10 ^ 8 J) / 36000 s = 66000 W = 66 kW.
Answer: 66 kW.
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