A friction force of 16 kN acts on a car with a mass of 2 tons. what is the initial speed of the car

A friction force of 16 kN acts on a car with a mass of 2 tons. what is the initial speed of the car if its stopping distance is 50m?

m = 2 tons = 2000 kilograms – vehicle weight;

Friction = 16 kN = 16000 Newton – the friction force acting on the car;

S = 50 meters – braking distance of the vehicle.

It is required to determine the initial vehicle speed before braking v (m / s).

Let’s find the acceleration with which the car brakes:

a = F friction / m = 16000/2000 = 8 m / s ^ 2.

Then the initial speed of the car will be equal to:

v = (2 * S * a) ^ 0.5 = (2 * 8 * 50) ^ 0.5 = 800 ^ 0.5 = 28.3 m / s.

Answer: The initial speed of the car is 28.3 meters per second.