A full cylinder weighing 2 kg rolls along a horizontal surface at a speed of 20 m / s. Determine the force that must

A full cylinder weighing 2 kg rolls along a horizontal surface at a speed of 20 m / s. Determine the force that must be applied to the barrel to stop it on the 1.6m path.

First, we find the time after which the cylinder should stop
t = S / V
t = 1.6 / 20 = 0.08 (s)
Now, with the help of mass and speed, we find the momentum of the body
p = m * V
p = 2/20 = 0.1 (kg * m / s)
Now, according to the law of conservation of momentum, we equate two impulses (forces and bodies)
p = p
And, because the impulse of force is
p = F * t
We write this formula and equate, and so we find the strength
F * t = p
F * 0.08 = 0.1
F = 0.1 / 0.08
F = 1.25 (H)
Answer: F = 1.25 (H)