A galvanic cell with an EMF of 1.5 V and an internal resistance of 10 m is closed to an external

A galvanic cell with an EMF of 1.5 V and an internal resistance of 10 m is closed to an external resistor of 40 m. Calculate the amperage in the circuit.

To find out the required current in the created circuit, we will use the formula: Iх = ε / (r + R), where ε is the EMF (ε = 1.5 V); r is the internal resistance of the galvanic cell used (r = 1 Ohm); R is the resistance (external) of the resistor (R = 4 ohms).

Let’s perform the calculation: Iх = ε / (r + R) = 1.5 / (1 + 4) = 0.3 A.

Answer: The current that flows in the created circuit should be 0.3 A.