A gas with a volume of 2 m3, which is at a constant pressure of 400 kPa, has expanded

A gas with a volume of 2 m3, which is at a constant pressure of 400 kPa, has expanded isobarically to 4 m3. Find a work perfect with a gas.

V1 = 2 m ^ 3.
V2 = 4 m ^ 3.
p = 400 kPa = 400000 Pa.
A -?
Isobaric is a process in which the mass of the gas and the pressure of the gas remain unchanged.
For an isobaric process, the work of gas A is determined by the formula: A = p * ΔV, where p is the gas pressure, ΔV is the change in gas volume.
ΔV = V2 – V1.
A = p * (V2 – V1).
A = 400,000 Pa * (4 m ^ 3 – 2 m ^ 3) = 800,000 J.
Answer: the gas did the job A = 800,000 J.