A given triangle ABC is isosceles with base AC. angle A and angle C = 156 degrees. Find-angles of triangle ABC.

The outer angle BAE of triangle ABC is adjacent to the inner angle BAC, the sum of which is 180.

Then the angle BAC = (180 – BAE) = (180 – 156) = 24.

Since the triangle ABC is isosceles with the base of the AC, the angle BCA = BAC = 24.

The sum of the inner angles of the triangle is 180, then the angle ABC = (180 – BAC – BCA) = (180 – 24 – 24) = 132.

Answer: The angles of the triangle ABC are 24, 132, 24.



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