A glass ball weighing 2 kg was dipped into kerosene. Determine its weight in kerosene.

The weight of the glass ball in kerosene will be equal to the difference between two directly opposite forces: the force of gravity and the buoyancy force of Archimedes.
Р = Fт – Fa = m * g – ρк * g * V, where m is the mass of the glass ball (m = 2kg), g is the acceleration of gravity (g = 9.8 m / s ^ 2), ρ is the density of kerosene (ρ = 800 kg / m ^ 3), V is the volume of the glass sphere (V = m / ρst, where ρst is the density of the glass (ρst = 2600 kg / m ^ 3)).
Р = m * g – ρк * g * V = m * g – ρк * g * m / ρst = 2 * 9.8 – 800 * 9.8 * 2/2600 = 19.6 – 6 = 13.6 N …
Answer: The weight of the glass ball is 13.6 N.