A glass bottle with a capacity of 0.5 liters and weighing 200 grams floats in water.

A glass bottle with a capacity of 0.5 liters and weighing 200 grams floats in water. How much water needs to be poured into the bottle for it to drown.

Given:

V = 0.5 liters = 0.0005 m3 (cubic meters) – the volume of the glass bottle;

m = 200 grams = 0.2 kilograms – the mass of the glass bottle;

ro = 1000 kg / m3 (kilogram per cubic meter) – water density.

It is required to determine m1 (kilogram) – how much water must be added to the bottle so that it drowns.

The bottle is acted upon by gravity, which tends to drown it (directed downward) and a buoyant force, which tends to lift it (directed upward). Then, for the bottle to sink, the following condition must be met:

F gravity = Farchimedes;

(m + m1) * g = V * g * ro, where g = 9.8 Newton / kilogram;

m + m1 = V * ro;

m1 = V * ro – m;

m1 = 0.0005 * 1000 – 0.2;

m1 = 0.5 – 0.2;

m1 = 0.3 kilograms.

Answer: in order for the bottle to drown, it is necessary to add 0.3 kilograms of water into it.