A glass of water with a volume of 250 ml was poured into the Pacific Ocean, the volume of water in which

A glass of water with a volume of 250 ml was poured into the Pacific Ocean, the volume of water in which is approximately 7.2 × 10^8 km3, waited until the water was well mixed, and again scooped up a glass of water. How many water molecules from those in the glass got back into it?

Let’s translate into the values needed for the solution:
Vs = 250 ml = 0.25 l = 0.25 dm³ = 0.25 * 10 ^ -3 m³;
Vo = 7.2 * 10 ^ 8 km³ = 7.2 * 10 ^ 8 * 10 ^ 9 m³ = 7.2 * 10 ^ 17 m³;
Let’s write the formula for solving the problem:
N₁ = Na * Vc / (22.4 * 10 ^ -3);
It turns out that the number of molecules from the original in the glass is:
N₁ = Na * Vc / (V + V);
Let’s transform:
N₁ = Na * Na * Vc / (V + V);
Let’s substitute:
N₁ = 6.02 * 10 ^ 23 * (0.25 * 10 ^ -3) ^ 2 / 22.4 * 10 ^ -3 * (7.2 * 10 ^ 17 + 0.25 * 10 ^ -3) ;
We get:
N₁ = 2.33;
Answer: N₁ = 2.33.