A granite beam weighing 1.3 t is partially submerged in water. In water, an Archimedean force of 1 kN

A granite beam weighing 1.3 t is partially submerged in water. In water, an Archimedean force of 1 kN acts on the beam. What part of the beam is above the water?

Given: m (mass of a granite beam) = 1.3 t (in SI m = 1300 kg); Fa (acting Archimedean force) = 1 kN (1000 N).

Constants: g (acceleration due to gravity) ≈ 10 m / s2; ρg (density of granite) = 2600 kg / m3; ρw (water density) = 1000 kg / m3.

The part of the granite beam under consideration, which is located above the water: k = 1 – Vsub / V = 1 – Fa / (ρw * g) / (m / ρg) = 1 – Fa * ρg / (m * ρw * g).

Calculation: k = 1 – 1000 * 2600 / (1300 * 1000 * 10) = 1 – 1/5 = 4/5.

Answer: There are 4/5 of the beams above the water.