A guinea pig with fluffy hair, when crossed with an individual with smooth hair, gave 28 fluffy and 26 smooth-haired

A guinea pig with fluffy hair, when crossed with an individual with smooth hair, gave 28 fluffy and 26 smooth-haired offspring in the offspring. Determine the genotypes of the parents and offspring.

First, we write down briefly the problem statement. Swirling is the dominant gene, so let’s designate it as “A”, and smooth coat – the recessive gene “a”. Since the second guinea pig has smooth hair, we will designate its genotype as “aa”. We do not yet know what genotype the first guinea pig has, but the problem indicates that the offspring have 28 loose and 26 smooth-haired offspring, which means that the ratio is approximately 1: 1. That is, when splitting in the offspring there should be pigs “Aa” – curled and “aa” – smooth-haired. These conditions will be met when the first individual will also be “Aa”. Hence the genotypes of the parents are “Aa” and “aa”.