A hammer weighing 150 N falls freely onto the anvil from a height of 1.1 m.
| May 9, 2021 | education
A hammer weighing 150 N falls freely onto the anvil from a height of 1.1 m. Find the force of the blow if its duration is 0.015 s.
Given: P (hammer weight) = 150 N; h (drop height) = 1.1 m; t (duration of the hammer impact on the anvil) = 0.015 s.
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
1) Determine the mass of the hammer under consideration: m = P / g = 150/10 = 15 kg.
2) Calculate the speed of the hammer at the moment of impact: m * V2 / 2 = m * g * h, whence V = √ (2 * g * h) = √ (2 * 10 * 1.1) = 4.69 m / s …
3) Determine the impact force: F * t = m * V, whence F = m * V / t = 15 * 4.69 / 0.015 = 4690 N.
Answer: The impact force is 4690 N.
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