A hammer weighing 3 tons falls from a height of 2 m onto an iron blank. Determine how much the internal energy of the disc has increased, if all the heat released in this case went into heating it.
m = 3 t = 3000 kg.
h = 2 m.
g = 10 N / kg.
According to the condition of the problem, all the mechanical energy E during the fall of the hammer goes to increase the internal energy of the iron bar ΔW: E = ΔW.
Since the hammer was originally at rest, its mechanical energy consisted only of potential E = En.
Let us express the potential energy of the hammer En by the formula: En = m * g * h.
The change in the internal energy of the blank ΔW will be determined by the formula: ΔW = m * g * h.
ΔW = 3000 kg * 10 N / kg * 2 m = 60,000 J.
Answer: the internal energy of the blank will increase by ΔW = 60,000 J.
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