A hammer with a mass of 100 kg falls on the part from a height of 1.5 m. The blow lasts 5 seconds.

A hammer with a mass of 100 kg falls on the part from a height of 1.5 m. The blow lasts 5 seconds. What is the average impact force?

Task data: m (weight of the considered hammer) = 100 kg; h (drop height) = 1.5 m; t (duration of impact on the part) = 5 s.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The average impact force of the hammer under consideration on the part is expressed from the equality: F * t = m * V, whence F = m * V / t = m * √ (2 * g * h) / t.

Let’s calculate: F = 100 * √ (2 * 10 * 1.5) / 5 ≈ 109.5 N.

Answer: The average impact force is 109.5 N.