A heat engine with an efficiency of 12% performs work of 150 J. per cycle. Determine the amount of heat given

A heat engine with an efficiency of 12% performs work of 150 J. per cycle. Determine the amount of heat given to the refrigerator per cycle.

Given: n = 0.12 A ‘= 150 J
Find: Qx =?
Decision:
To begin with, let’s find the amount of heat received from the heater: n = A ‘/ Qn => Qn = A’ / n Qn = 150 J / 0.12 = 1250 J The efficiency can also be found by the formula: n = 1 – (Qx / Qn) 1 – n = Qx / Qn Qx = Qn * (1 – n) Qx = 1250 J * (1 – 0.12) Qx = 1100 J
Answer: Qx = 1100 J