A heat engine with an efficiency of 50% per cycle gives the refrigerator 100 J.

A heat engine with an efficiency of 50% per cycle gives the refrigerator 100 J. What amount of heat does the machine receive from the heater per cycle?

Given:
n = 50%
n = 0.5
Qx = 100J
Find: Qн =?
Decision:
n = 1 – (Qx / Qn)
1 + n = Qx / Qн
Qн = Qx / (n + 1)
Qн = 100 J / (0.5 + 1)
Qн = 100 J / 1.5
Qн ≈ 67 J
Answer: Qн = 67 J



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