A heated stone weighing 3 kg, cooling by 20 (degrees Celsius), gives off 24 kJ of energy

A heated stone weighing 3 kg, cooling by 20 (degrees Celsius), gives off 24 kJ of energy to the surrounding space. Determine the specific heat of the heat capacity of the stone

m = 3 kg.

Δt = 20 ° C.

Q = 24 kJ = 24000 J.

C -?

The amount of thermal energy Q, which is released during the cooling of the stone, is determined by the formula: Q = C * m * Δt.

C = Q / m * Δt.

C = 24000 J / 3 kg * 20 ° C = 400 J / kg * ° C.

Answer: the specific heat of the stone is C = 400 J / kg * ° C.



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