A heated stone weighing 3 kg, cooling by 20 degrees, gives 24 kJ of energy to the surrounding space.

A heated stone weighing 3 kg, cooling by 20 degrees, gives 24 kJ of energy to the surrounding space. Determine the specific heat of the stone.

Given:
m = 3 kilograms is the mass of the stone;
dT = 20 degrees – the temperature at which the stone cooled;
Q = 24 kJ = 24000 – the amount of energy transferred by the stone during cooling.
It is required to determine c (J / (kg * C)) – the specific heat capacity of the stone.
According to the laws of thermodynamics:
Q = c * m * dT, hence:
c = Q / (m * dT) = 24000 / (3 * 20) = 24000/60 = 400 J / (kg * C).
Answer: the specific heat capacity of the stone is 400 J / (kg * C).