A heated stone weighing 5 kg, cooling in water by 1 ° C, transfers 2.1 kJ of energy to it. What is the specific heat of the stone?

Given:
m = 5 kg
t = 1 ° C
Q = 2.1 kJ
Find: with -?
Decision:
We use the formula Q = cm∆t
Take out with = Q / m∆t
Q = 2100 J
s = 2100/5 * 1
s = 420 J / kg ° C



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