A helicopter steadily descending vertically downward at a speed of 36 km / h. An object was dropped that fell to the ground after 8 seconds, determine the height from which the object was thrown. Acceleration of free fall is taken equal to 10.
V0 = 36 km / h = 10 m / s.
t = 8 s.
g = 10 m / s2.
Since the object was in the helicopter, which descended uniformly downward at a speed V0, at the moment of the beginning of the fall, the body relative to the ground had a speed of V0.
Only gravity acts on the body, so it will move uniformly with the acceleration of gravity g.
The height of the fall of the object h is expressed by the formula: h = V0 * t + g * t ^ 2/2.
h = 10 m / s * 8 s + 10 m / s2 * (8 s) ^ 2/2 = 400 m.
Answer: the object fell from a helicopter from a height of h = 400 m.
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