A helicopter weighing m = 2000kg is at an altitude of h1 = 20m. At what height will its potential

A helicopter weighing m = 2000kg is at an altitude of h1 = 20m. At what height will its potential energy increase by ΔEp = 600 kJ?

m = 2000 kg.
ΔEp = 600 kJ = 600000 J.
g = 9.8 m / s ^ 2.
h2 -?
ΔEp = En2 – En1.
En2 = m * g * h2.
En1 = m * g * h1.
ΔЕп = m * g * h2 – m * g * h1.
m * g * h2 = ΔEn + m * g * h1.
h2 = (ΔEn + m * g * h1) / m * g.
h2 = (600000 J + 2000 kg * 9.8 m / s ^ 2 * 20 m) / 2000 kg * 9.8 m / s ^ 2 = 50.6 m.
Answer: at an altitude of h2 = 50.6 m, the potential energy of the helicopter will increase by 600,000 J.