A hollow steel ball weighing 1.2 kg has a volume of 200 cubic cm. What is the volume of the cavity?
| March 13, 2021 | education
To calculate the volume of a cavity in a steel ball, we will use the formula: Vp = Vf – Vst = Vf – m / ρst.
Values of constants and variables: Vf – the actual volume of the ball (Vf = 200 cm3 = 200 * 10-6 m3); m is the mass of the ball (m = 1.2 kg); ρst is the density of steel (ρst = 7800 kg / m3).
Let’s perform the calculation: Vp = Vph – m / ρst = 200 * 10-6 – 1.2 / 7800 = 4.615 * 10-5 m3 = 46.15 cm3.
Answer: The volume of the cavity of the taken steel ball is 46.15 cm3.
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