A horizontal vessel with a capacity of 20 liters was divided into 2 parts by a thin movable partition. On the left – 1 mole of water

A horizontal vessel with a capacity of 20 liters was divided into 2 parts by a thin movable partition. On the left – 1 mole of water, on the right – 1/2 mole of nitrogen. The temperature in the vessel is 100 degrees. Find the volume of nitrogen.

In this task, it is important to take into account that at 100 degrees the water boils.
Since the septum is at rest, then P1 = P2 = P.
The temperature is the same everywhere: T1 = T2 = T.
Let us write down the equations of state for both gases:
PV1 = ν1RT
PV1 = ν2RT
Let us express V2 (nitrogen):
V2 = (ν2RT) / P = (0.5 * 8.31 * 373) / 10 ^ 5 = 15.5 (m ^ 3)
Answer: V2 = 15.5 (m ^ 3)