A horizontally flying bullet weighing 10 g hit a 500 g wooden block lying on a smooth horizontal

| June 1, 2021 | education

A horizontally flying bullet weighing 10 g hit a 500 g wooden block lying on a smooth horizontal surface and got stuck in it. What was the speed of the bullet if the bar, after being hit by a bullet, acquired a speed of 10 m / s?

mp = 10 g = 0.01 kg.

mb = 500 g = 0.5 kg.

Vb “= 10 m / s.

Vп -?

Pn + Pb = Pn “+ Pb” – the law of conservation of momentum in vector form.

mp * Vp + mb * Vb = mp * Vp “+ mb * Vb”.

Since Vb = 0 m / s and Vp “= Vb”, the conservation law will take the form: mp * Vp = mp * Vb “+ mb * Vb”.

The formula for determining the speed of a bullet before hitting a wooden block Vp will be: Vp = (mp + mb) * Vb “/ mp.

Vp = (0.01 kg + 0.5 kg) * 10 m / s / 0.01 kg = 510 m / s.

Answer: the speed of the bullet before hitting the bar was Vp = 510 m / s.



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