A hummingbird weighing 20 g flies at a speed of 25 km / h. At what speed should an albatross weighing 8 kg

A hummingbird weighing 20 g flies at a speed of 25 km / h. At what speed should an albatross weighing 8 kg fly in order for the kinetic energy of its flight to be 1000 times greater than the kinetic energy of a hummingbird?

Kinetic energy of the body:
Ek = (m * V²) / 2, m – body mass, V – body speed.
Hummingbird:
Ek1 = (m1 * V1²) / 2, where m1 = 20 g = 0.02 kg, V1 = 25 km / h.
Albatross:
Ek2 = (m2 * V2²) / 2, where m2 = 8 kg.
Ek2 = 1000Ek1:
(m1 * V1²) / 2 = 1000 * (m2 * V2²) / 2.
1000 * m1 * V1² = m2 * V2².
V2² = 1000 * m1 * V1² / m2.
V2 = sqrt (1000 * m1 * V1² / m2) = sqrt (1000 * 0.02 * 25² / 8) = 39.53 km / h (11 m / s).
Answer: The albatross must fly at a speed of 39.83 km / h (11 m / s).