A hunter weighing 60 kg, standing on smooth ice, shoots a gun in a horizontal direction. Charge weight 0.03 kg

A hunter weighing 60 kg, standing on smooth ice, shoots a gun in a horizontal direction. Charge weight 0.03 kg. The speed of the pellets when fired is 300 m / s. What is the speed of the hunter after firing?

Given:

m1 = 60 kilograms – the mass of a hunter standing on smooth ice;

m2 = 0.03 kilograms – the mass of the charge;

v2 = 300 meters per second – the speed of the pellets when fired.

It is required to determine v1 (meter per second) – the speed of the hunter after the shot.

To determine the speed of the hunter, you must use the following formula (the law of conservation of momentum):

m1 * v1 = m2 * v2, from here we find that:

v1 = m2 * v2 / m1 = 0.03 * 300/60 = 9/60 = 0.15 meters / second.

Answer: the speed of the hunter after the shot will be equal to 0.15 meters per second.