A hydrocarbon with a nitrogen density of 2.071 contains 82.76% carbon.

A hydrocarbon with a nitrogen density of 2.071 contains 82.76% carbon. Determine the molecular formula of the hydrocarbon, write the structural formula and its name.

Let’s implement the solution:
1. Let’s write down the hydrocarbon formula schematically:
2. Determine the molecular weight:
M (CxHy) = M (N2) * D (N2) = 28 * 2.071 = 57.98 g / mol = 58 g / mol.
3.Calculate the number of moles of carbon, hydrogen:
Y (C) = m / M = 82.76 / 12 = 6.89 mol;
m (H) = 100-57.98 = 42.02 g;
Y (H) = 42.02 / 1 = 42.02 mol.
4. Ratio: X: Y = C: H = 6.89: 42.02 = 1: 6 (divided by the smaller number 6.89). The simplest formula is CH6.
5. Let’s derive the molecular formula based on the general: СnH2n + 2;
CnH2n + 2 = 58;
12n + 2 + 2 = 58;
12n = 54;
n = 4.5
Answer:
C4H10 – butane. M (C4H10) = 58 g / mol.
CH3 – CH2 – CH2 – CH3 is the abbreviated structural formula of butane.