A hypothetical progression is given 2; 4; 8. 1) find the sixth term in the progression.

A hypothetical progression is given 2; 4; 8. 1) find the sixth term in the progression. 2) find the sum of the first six terms of the progression.

As you can see from the condition, the first term of the progression is equal to 2, each next one is obtained from the previous one by multiplying it by 2.

1) find the sixth term of the progression:

2; 4; eight; 16; 32; 64.

2) the sum of the first six members of the progression will be equal to:

2 + 4 + 8 + 16 + 32 + 64 = 126.

Answer: the sixth term of the progression is 64;

the sum of the first six members of the progression is 128.



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