A jet plane flies at a speed of 900 km / h and a path of 1800 km, consuming 4 tons of fuel.

A jet plane flies at a speed of 900 km / h and a path of 1800 km, consuming 4 tons of fuel. The aircraft’s engine power is 5.9 MW, its efficiency is 23%. Determine the specific heat of combustion of this fuel?

Data: V (aircraft speed) = 900 km / h = 250 m / s; S (distance traveled) = 1800 km = 1800 * 10 ^ 3 m; m (mass of fuel consumed) = 4 t = 4 * 10 ^ 3 kg; N (engine power) = 5.9 MW = 5.9 * 10 ^ 6 W; η (motor efficiency) = 23% = 0.23.

To calculate the specific heat of combustion of the fuel used, we use the formula: η = N / Nz = N / (A / t) = N / (m * q / (S / V)) = N * S / (m * q * V) and q = N * S / (m * V * η).

Calculation: q = 5.9 * 10 ^ 6 * 1800 * 10 ^ 3 / (4 * 10 ^ 3 * 250 * 0.23) = 46.17 * 10 ^ 6 J / kg.