A lamp with a resistance of 16 ohms and a rheostat with a resistance of 10 ohms are connected in parallel

| June 18, 2021 | education

A lamp with a resistance of 16 ohms and a rheostat with a resistance of 10 ohms are connected in parallel and connected to a circuit with a current strength of 0.26 A. Determine the voltage across the lamp.

Rl = 16 ohms.

Rp = 10 Ohm.

I = 0.26 A.

Uл -?

With parallel connection of conductors, the total resistance of the circuit R will be determined by the formula: R = Rl * Rp / (Rl + Rp).

The voltage with parallel connection of conductors on all conductors and in the circuit is the same: U = Ul = Uр.

Let’s write Ohm’s law for a section of the circuit: I = U / R = U * (Rl + Rp) / Rl * Rp.

U = I * Rl * Rp / (Rl + Rp).

U = 0.26 A * 16 Ohm * 10 Ohm / (16 Ohm + 10 Ohm) = 1.6 V.

Since U = Ul = Uр, then Ul = 1.6 V.

Answer: the voltage across the lamp is Ul = 1.6 V.



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