A lead ball with a mass of 500 g was moving at a speed of 10 m / s and collided inelastically with an immobile

univerkov | August 10, 2021 | education

A lead ball with a mass of 500 g was moving at a speed of 10 m / s and collided inelastically with an immobile ball with a mass of 200 g. Find the kinetic energy of both balls after the collision.

Data: m1 (mass of a movable lead ball) = 500 g (in SI m1 = 0.5 kg); V1 (initial speed of the lead ball) = 10 m / s; inelastic collision; m2 (mass of a stationary ball) = 200 g (in SI m2 = 0.2 kg).

1) Velocity after inelastic collision: (m1 + m2) * V = m1 * V and V = m1 * V / (m1 + m2) = 0.5 * 10 / (0.5 + 0.2) = 7.14 m / s.

2) Kinetic energy: Ek = (m1 + m2) * V ^ 2/2 = 17.86 J.

Answer: After an inelastic collision, the kinetic energy of two given balls will be 17.86 J.

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