A lead bullet falls from a height of 30 m onto a steel plate. How much will the bullet heat up if 50%

A lead bullet falls from a height of 30 m onto a steel plate. How much will the bullet heat up if 50% of the mechanical energy has passed into the internal energy of the bullet?

Initial data: h (height from which the lead bullet fell) = 30 m; Q = 50% Ecomplete

Constants: C (specific heat capacity of lead) = 140 J / (kg * K); g (acceleration due to gravity) = 10 m / s ^ 2.

When falling, the potential energy of a lead bullet will completely turn into kinetic energy, and when it hits a steel plate, kinetic energy (50%) will turn into heat energy.

0.5Ep = 0.5Ek = Q.

0.5 * m * g * h = C * m * Δt.

Δt = 0.5 * g * h / C = 0.5 * 10 * 30/140 = 1.07 ºС.

Answer: The lead bullet will heat up to 1.07 ° C.