A lead pellet, flying at a speed of 100 m / s, hit the wall and got stuck in it, while 52% of the heat released during the impact was used to heat it.
Data: V (the speed with which the lead pellet flew) = 100 m / s; η (percentage of the kinetic energy of the pellet that goes into heating it) = 52% (0.52).
Constants: Cc (specific heat of lead) = 130 J / (kg * K).
The increase in the temperature of the lead pellet is determined from the equality: Q = η * Ek and Cc * m * Δt = η * m * V ^ 2/2, whence Δt = η * m * V ^ 2 / (2 * Cc * m) = η * V2 / (2 * Cc).
Calculation: Δt = 0.52 * 100 ^ 2 / (2 * 130) = 20 ºС.
Answer: The temperature of the lead pellet has increased by 20 ºС.
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