A line CP is drawn through vertex C of triangle CDE with right angle D, parallel to the side DE.

A line CP is drawn through vertex C of triangle CDE with right angle D, parallel to the side DE. Find the angles C and E of the triangle if the angle PCE = 49 degrees.

Since the line CP is parallel to the side DE, that is, another line, then the angle DСР will be rectangular (90 °).

Let’s find the value of the angle DCE of the triangle:

90 – 49 = 51 °

Let’s find the value of the angle DEC, triangle (DEC = 180 ° – CDE – DCE):

180 – 90 – 51 = 39 °

Answer: 51 ° and 39 °.