A liter of 1 solution contains 20 g of salt, a liter of another solution in 3 more mixed 5 liters

A liter of 1 solution contains 20 g of salt, a liter of another solution in 3 more mixed 5 liters of 1 solution and 3 liters 2 how many grams of salt is contained in the new solution.

First, we find the amount of salt in one liter of the second solution.

Since it is 3 times more than in the first, we get:

20 * 3 = 60 grams.

We find the amount of salt in 5 liters of the first solution.

To do this, multiply the amount of salt in 1 liter of solution by 5 liters.

We get:

20 * 5 = 100 grams.

Similarly, we find the amount of salt in 3 liters of the second solution.

We get:

60 * 3 = 180 grams.

Find the total amount of salt in the resulting solution after mixing.

100 + 180 = 280 grams of salt.

Answer: The new solution contains 280 grams of salt.