A load is dropped from a balloon descending vertically downward at a speed of 8 m / s, which reaches
| August 4, 2021 | education
A load is dropped from a balloon descending vertically downward at a speed of 8 m / s, which reaches the surface of the earth after 4 s. How high is the ball at the moment of dropping? how fast will the load hit the ground?
The speed of the load v0 at the moment of dropping is directed downward and is equal to the speed of lowering the balloon, that is, 8 m. The acceleration of the load is also directed downward and is equal to the acceleration of gravity g = 9.8 m / s2. The required height means:
H = v0t + gt ^ 2/2 = 8 * 4 + 9.8 * 4 ^ 2/2 = 110.4 m.
Final speed of the load at the time of landing:
v = v0 + gt = 8 + 9.8 * 4 = 47.2 m / s.
Answer: H = 110.4 m, v = 47.2 m / s.
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