A load is thrown from an airplane flying horizontally at a speed of 144 km / h.

A load is thrown from an airplane flying horizontally at a speed of 144 km / h. Find the speed of the load relative to the ground after 3 s of fall. Neglect the air resistance.

These tasks: Vg (horizontal speed of the aircraft, the considered cargo) = 144 km / h = 40 m / s; t (duration of the fall of the load) = 3 s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Vertical speed acquired by the load: Vw = g * t = 10 * 3 = 30 m / s.

2) The speed of the load under consideration relative to the ground: Vz = √ (Vv ^ 2 + Vg ^ 2) = √ (30 ^ 2 + 40 ^ 2) = 50 m / s.

Answer: In 3 s after the beginning of the fall, the considered load will have a speed of 50 m / s relative to the ground.