A load of 1200N is suspended from the short arm, while lifting it by 12 cm, a force of 360N was applied to the long arm

| April 9, 2021 | education

A load of 1200N is suspended from the short arm, while lifting it by 12 cm, a force of 360N was applied to the long arm, while the application of force shifted by 50 cm. Calculate the efficiency of the lever?

The efficiency of the lever η = Apol / Azat, where Apol is the useful work of lifting the weight, performed by the short arm Apol = P ∙ h, Azat is the work spent on lifting the lever together with the load, Azat = F ∙ S. We get: η = (R ∙ h) / (F ∙ S). From the condition of the problem, it is known that a load P = 1200N is suspended from the short arm, when it is raised to a height of h = 12 cm = 0.12 m, a force F = 360N was applied to the long arm, while applying force, the long arm moved to a distance S = 50 cm = 0.5 m. Substitute the values ​​of physical quantities in the formula and make calculations: η = (1200 ∙ 0.12) / (360 ∙ 0.5); η = 0.8 = 80%.
Answer: The efficiency of this lever is 80%.



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