A load on a spring oscillates with an amplitude of 50 cm. It is known that starting its movement from

A load on a spring oscillates with an amplitude of 50 cm. It is known that starting its movement from the extreme point of the trajectory, the load travels a path of 1.5 m in 6 seconds. Determine the frequency of oscillations

Amplitude is the maximum one-way deviation from the equilibrium position. For a full swing, the load must travel a distance equal to four maximum amplitudes:
from one extreme position to another through the equilibrium point – 2 amplitudes,
return to starting position – 2 amplitudes.
In our case:
s = 0.5 m * 4 = 2 m.
We make the proportion:

1.5 m – 6 s;
2 m – T c.

T = (2 m * 6 s) / 1.5 m = 8 s.

Frequency f is the reciprocal of the oscillation period:
f = 1 / T = 1/8 c = 0.125 Hz.

Answer: 0.125 Hz.