A load suspended on a spring with a stiffness of 300 N / m led to its elongation by 4 cm. Is the weight of the load equal to?

The force of elasticity of the spring will be balanced by the action of the force of gravity, the value of which will be equal to the weight of the load.
Fcont. = Fт., Where Fcont. = k * ∆l (k is the stiffness of the spring, k = 300 N / m, ∆l = the amount of deformation (elongation), ∆l = 4 cm = 0.04 m), Ft = P = m * g.
Let’s calculate the weight of the cargo:
P = Fcont. = k * ∆l = 300 * 0.04 = 12 N.
Check: H = (N / m) * m = N.
Answer. The weight of the load is 12 N.