A load was dropped from a stationary helicopter at an altitude of 245 m.

A load was dropped from a stationary helicopter at an altitude of 245 m. How long will it take for the load to fall to the surface of the Earth?

These tasks: h (the path covered by the cargo; the height of the helicopter above the surface) = 245 m; the helicopter is stationary, therefore, V0 (initial speed of the fall of the load) = 0 m / s.

Reference values: g (acceleration of gravity, acceleration of the load) ≈ 10 m / s2.

The duration of the fall of the load from a stationary helicopter can be expressed from the formula: S = h = V0 * t + g * t ^ 2/2 = g * t ^ 2/2 and t = √ (2h / g).

Calculation: t = √ (2 * 245/10) = 7 s.

Answer: The cargo will fall to the surface of the Earth in 7 seconds.