A load weighing 0.1 kg and a volume of 10 cm3 is suspended from the thread.

A load weighing 0.1 kg and a volume of 10 cm3 is suspended from the thread. the load is lowered into the water. What is the tension force of the thread?

m = 0.1 kilogram is the mass of the cargo;

g = 10 Newton / kilogram – acceleration of gravity;

V = 10 cubic centimeters = 10-5 cubic meters – the volume of the cargo;

ro = 1000 kilograms / cubic meter – density of water.

It is required to determine T (Newton) – the tension force of the thread.

Let’s find all the forces acting on the load:

T + Farchimedes – F gravity = 0, where T is the tension force of the thread (directed upwards), Farchimedes is the buoyancy force (directed upwards) and F gravity is the gravity force acting on the load (directed downwards). Then:

T = F gravity – Farchimedes;

T = m * g – ro * g * V;

T = 0.1 * 10 – 1000 * 10 * 10-5 = 1 – 0.1 = 0.9 Newton.

Answer: the tensile force of the thread is 0.9 Newton.