A load weighing 0.5 kg is suspended on a dynamometer. With what elastic force does the dynamometer act on the load

A load weighing 0.5 kg is suspended on a dynamometer. With what elastic force does the dynamometer act on the load if it is lifted together with the load with an acceleration of 3 m / s²?

Data: mg – weight of the load on the dynamometer (mg = 0.5 kg); a – acceleration of the load and the dynamometer during lifting (a = 3 m / s2).

Const: g – acceleration due to gravity (g ≈ 9.8 m / s2).

To find out the effective elastic force, consider the projection of forces: mg * a = Fel – Ft, from where we express: Fel = mg * a + Ft = mg * a + mg * g = (a + g) * mg.

Let’s perform the calculation: Fcont = (a + g) * mg = (3 + 9.8) * 0.5 = 6.4 N.

Answer: The load acts on the dynamometer with an elastic force of 6.4 N.