A load weighing 10 kg moves on a horizontal plane under the action of a force of 50N directed to the floor

A load weighing 10 kg moves on a horizontal plane under the action of a force of 50N directed to the floor at an angle of 60 degrees to the horizontal. Determine the acceleration of the load. friction is negligible.

m = 10 kg.

g = 10 m / s2.

∠α = 60 °.

F = 50 N.

a -?

According to 2 Newton’s law, the acceleration of a body a is directly proportional to the resultant of all forces Frv that act on the body, and inversely proportional to the mass of the body m: a = Frv / m.

When moving, 3 forces act on the body: the force F with which the body is pulled, the gravity force m * g, the reaction force of the surface N.

Frav = F + m * g + N.

m * a = F + m * g + N – 2 Newton’s law in vector form.

OH: m * a = F * cosα.

OU: 0 = F * sinα – m * g + N.

The acceleration of the body a will be determined by the formula: a = F * cosα / m.

a = 50 N * cos60 ° / 10 kg = 2.5 m / s2.

Answer: the body will move with acceleration a = 2.5 m / s2.