A load weighing 100 g is evenly lifted by means of a spring with a stiffness of 100 N / m. How much is the spring stretched?

Initial data: m (cargo weight) = 100 g; k (coefficient of spring stiffness) = 100 N / m.

Reference data: g (acceleration due to gravity) = 10 m / s ^ 2.

SI system: m = 100 g = 0.1 kg.

The force of elasticity of the spring will balance the force of gravity that acts on the load: Fbr. = Fт = k * Δl = m * g, whence Δl (spring tension) = m * g / k.

Let’s calculate: Δl = 0.1 * 10/100 = 0.01 m or 1 cm.

Answer: The spring is stretched 0.01 m (1 cm).