A load weighing 100 kg is lifted on a rope with an acceleration of 0.1 m / s ^ 2. Find the elastic force arising in the rope.
| November 23, 2020 | education
according to Newton’s second law: F = ma, where F is the resultant.
there are only two forces in the problem – gravity Ftyach = mg and rope tension T.
gravity is downward and tension is upward.
By projecting onto the axis, we get T = ma + mg.
T = 100kg * (0.1m / s ^ 2 + 10m / s ^ 2) = 1010 N
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